递归遍历至此结束。
3、非递归遍历
非递归遍历在操作中不需要递归方法的参与即可实现Tree的拼接
对于以上的代码,我们不需要修改,只需要定义一个非递归遍历方法NotRecursion:
public static void NotRecursion()
{
#region 非递归遍历
System.Diagnostics.Stopwatch sw2 = new System.Diagnostics.Stopwatch();
sw2.Start();
Dictionary<string, TreeObejct> dtoMap = new Dictionary<string, TreeObejct>();
foreach (var item in models)
{
dtoMap.Add(item.id, item);
}
IList<TreeObejct> result = new List<TreeObejct>();
foreach (var item in dtoMap.Values)
{
if (item.pId == "0")
{
result.Add(item);
}
else
{
if (dtoMap.ContainsKey(item.pId))
{
dtoMap[item.pId].AddChilrden(item);
}
}
}
sw2.Stop();
Console.WriteLine("----------非递归遍历用时:" + sw2.ElapsedMilliseconds + "----------线程名称:" + t2.Name + ",线程ID:" + t2.ManagedThreadId);
#endregion
}
编写main函数:
private static IList<TreeObejct> models;
private static IList<TreeObejct> models2;
private static Thread t1;
private static Thread t2;
static void Main(string[] args)
{
int count = 6;
Console.WriteLine("生成任务数:"+count+"个");
models = GetData(count);
models2 = GetData(count);
t1 = new Thread(Recursion);
t2 = new Thread(NotRecursion);
t1.Name = "递归遍历";
t2.Name = "非递归遍历";
t1.Start();
t2.Start();
Console.Read();
}
启动查看执行结果:

发现一个问题,递归3s,非递归0s,随后我又进行了更多的测试:
执行时间测试
| 任务个数 | 递归(ms) | 非递归(ms) |
| 6 | 3 | 0 |
| 6 | 1 | 0 |
| 6 | 1 | 0 |
| 101 | 1 | 0 |
| 101 | 4 | 0 |
| 101 | 5 | 0 |
| 1001 | 196 | 5 |
| 1001 | 413 | 1 |
| 1001 | 233 | 7 |
| 5001 | 4667 | 5 |
| 5001 | 4645 | 28 |
| 5001 | 5055 | 7 |
| 10001 | StackOverflowException | 66 |
| 10001 | StackOverflowException | 81 |
| 10001 | StackOverflowException | 69 |
| 50001 | - | 46 |
| 50001 | - | 47 |
| 50001 | - | 42 |
| 100001 | - | 160 |
| 100001 | - | 133 |
| 100001 | - | 129 |










