关于使用Redisson订阅数问题

2022-06-05 21:30:26

目录一、前提二、源码分析1、RedissonLock#lock()方法2、详细看下subscribe()方法3、回到subscribe()方法主要逻辑还是交给了LockPubSub#subscri...

目录
一、前提
二、源码分析
1、RedissonLock#lock() 方法
2、详细看下subscribe()方法
3、回到subscribe()方法主要逻辑还是交给了 LockPubSub#subscribe()里面
4、PublishSubscribeService#subscribe逻辑如下:
三 总结

一、前提

最近在使用分布式锁redisson时遇到一个线上问题:发现是subscriptionsPerConnection or subscriptionConnectionPoolSize 的大小不够,需要提高配置才能解决。

二、源码分析

下面对其源码进行分析,才能找到到底是什么逻辑导致问题所在:

1、RedissonLock#lock() 方法

private void lock(long leaseTime, TimeUnit unit, boolean interruptibly) throws InterruptedException {
    long threadId = Thread.currentThread().getId();
    // 尝试获取,如果ttl == null,则表示获取锁成功
    Long ttl = tryAcquire(leaseTime, unit, threadId);
    // lock acquired
    if (ttl == null) {
      return;
    }

    // 订阅锁释放事件,并通过await方法阻塞等待锁释放,有效的解决了无效的锁申请浪费资源的问题
    RFuture<RedissonLockEntry> future = subscribe(threadId);
    if (interruptibly) {
      commandExecutor.syncSubscriptionInterrupted(future);
    } else {
      commandExecutor.syncSubscription(future);
    }

    // 后面代码忽略
    try {
      // 无限循环获取锁,直到获取锁成功
      // ...
    } finally {
      // 取消订阅锁释放事件
      unsubscribe(future, threadId);
    }
}

总结下主要逻辑:

获取当前线程的线程id;
tryAquire尝试获取锁,并返回ttl
如果ttl为空,则结束流程;否则进入后续逻辑;
this.subscribe(threadId)订阅当前线程,返回一个RFuture;
如果在指定时间没有监听到,则会产生如上异常。
订阅成功后, 通过while(true)循环,一直尝试获取锁
fially代码块,会解除订阅

所以上述这情况问题应该出现在subscribe()方法中

2、详细看下subscribe()方法

protected RFuture<RedissonLockEntry> subscribe(long threadId) {
  // entryName 格式:“id:name”;
  // channelName 格式:“redisson_lock__channel:name”;
  return pubSub.subscribe(getEntryName(), getChannelName());
}

RedissonLock#pubSub 是在RedissonLock构造函数中初始化的:

public RedissonLock(CommandAsyncExecutor commandExecutor, String name) {
  // ....
  this.pubSub = commandExecutor.getConnectionManager().getSubscribeService().getLockPubSub();
}

而subscribeService在MasterSlaveConnectionManager的实现中又是通过如下方式构造的

public MasterSlaveConnectionManager(MasterSlaveServersConfig cfg, Config config, UUID id) {
  this(config, id);
  this.config = cfg;

  // 初始化
  initTimer(cfg);
  initSingleEntry();
}

protected void initTimer(MasterSlaveServersConfig config) {
  int[] timeouts = new int[]{config.getRetryInterval(), config.getTimeout()};
  Arrays.sort(timeouts);
  int minTimeout = timeouts[0];
  if (minTimeout % 100 != 0) {
    minTimeout = (minTimeout % 100) / 2;
  } else if (minTimeout == 100) {
    minTimeout = 50;
  } else {
    minTimeout = 100;
  }

  timer = new HashedWheelTimer(new DefaultThreadFactory("redisson-timer"), minTimeout, TimeUnit.MILLISECONDS, 1024, false);

  connectionWatcher = new IdleConnectionWatcher(this, config);

  // 初始化:其中this就是MasterSlaveConnectionManager实例,config则为MasterSlaveServersConfig实例:
  subscribeService = new PublishSubscribeService(this, config);
}

PublishSubscribeService构造函数

private final SemaphorePubSub semaphorePubSub = new SemaphorePubSub(this);
public PublishSubscribeService(ConnectionManager connectionManager, MasterSlaveServersConfig config) {
  super();
  this.connectionManager = connectionManager;
  this.config = config;
  for (int i = 0; i < locks.length; i++) {
    // 这里初始化了一组信号量,每个信号量的初始值为1
    locks[i] = new AsyncSemaphore(1);
  }
}

3、回到subscribe()方法主要逻辑还是交给了 LockPubSub#subscribe()里面

private final ConcurrentMap<String, E> entries = new ConcurrentHashMap<>();

public RFuture<E> subscribe(String entryName, String channelName) {
   // 从PublishSubscribeService获取对应的信号量。 相同的channelName获取的是同一个信号量
  // public AsyncSemaphore getSemaphore(ChannelName channelName) {
  //  return locks[Math.abs(channelName.hashCode() % locks.length)];
  // }
  AsyncSemaphore semaphore = service.getSemaphore(new ChannelName(channelName));

  AtomicReference<Runnable> listenerHolder = new AtomicReference<Runnable>();  
  RPromise<E> newPromise = new RedissonPromise<E>() {
    @Override
    public boolean cancel(boolean mayInterruptIfRunning) {
      return semaphore.remove(listenerHolder.get());
    }
  };

  Runnable listener = new Runnable() {

    @Override
    public void run() {
      // 如果存在RedissonLockEntry, 则直接利用已有的监听
      E entry = entries.get(entryName);
      if (entry != null) {
        entry.acquire();
        semaphore.release();
        entry.getPromise().onComplete(new TransferListener<E>(newPromise));
        return;
      }

      E value = createEntry(newPromise);
      value.acquire();

      E oldValue = entries.putIfAbsent(entryName, value);
      if (oldValue != null) {
        oldValue.acquire();
        semaphore.release();
        oldValue.getPromise().onComplete(new TransferListener<E>(newPromise));
        return;
      }

      // 创建监听,
      RedisPubSubListener<Object> listener = createListener(channelName, value);
      // 订阅监听
      service.subscribe(LongCodec.INSTANCE, channelName, semaphore, listener);
    }
  };

  // 最终会执行listener.run方法
  semaphore.acquire(listener);
  listenerHolder.set(listener);

  return newPromise;
}

AsyncSemaphore#acquire()方法

public void acquire(Runnable listener) {
  acquire(listener, 1);
}

public void acquire(Runnable listener, int permits) {
  boolean run = false;

  synchronized (this) {
    // counter初始化值为1
    if (counter < permits) {
      // 如果不是第一次执行,则将listener加入到listeners集合中
      listeners.add(new Entry(listener, permits));
      return;
    } else {
      counter -= permits;
      run = true;
    }
  }

  // 第一次执行acquire, 才会执行listener.run()方法
  if (run) {
    listener.run();
  }
}

梳理上述逻辑:

1、从PublishSubscribeService获取对应的信号量, 相同的channelName获取的是同一个信号量
2、如果是第一次请求,则会立马执行listener.run()方法, 否则需要等上个线程获取到该信号量执行完方能执行;
3、如果已经存在RedissonLockEntry, 则利用已经订阅就行
4、如果不存在RedissonLockEntry, 则会创建新的RedissonLockEntry,然后进行。

从上面代码看,主要逻辑是交给了PublishSubscribeService#subscribe方法

4、PublishSubscribeService#subscribe逻辑如下:

private final ConcurrentMap<ChannelName, PubSubConnectionEntry> name2PubSubConnection = new ConcurrentHashMap<>();
private final Queue<PubSubConnectionEntry> freePubSubConnections = new ConcurrentLinkedQueue<>();

public RFuture<PubSubConnectionEntry> subscribe(Codec codec, String channelName, AsyncSemaphore semaphore, RedisPubSubListener<?>... listeners) {
  RPromise<PubSubConnectionEntry> promise = new RedissonPromise<PubSubConnectionEntry>();
  // 主要逻辑入口, 这里要主要channelName每次都是新对象, 但内部覆写hashCode+equals。
  subscribe(codec, new ChannelName(channelName), promise, PubSubType.SUBSCRIBE, semaphore, listeners);
  return promise;
}

private void subscribe(Codec codec, ChannelName channelName, RPromise<PubSubConnectionEntry> promise, PubSubType type, AsyncSemaphore lock, RedisPubSubListener<?>... listeners) {

  PubSubConnectionEntry connEntry = name2PubSubConnection.get(channelName);
  if (connEntry != null) {
    // 从已有Connection中取,如果存在直接把listeners加入到PubSubConnectionEntry中
    addListeners(channelName, promise, type, lock, connEntry, listeners);
    return;
  }

  // 没有时,才是最重要的逻辑
  freePubSubLock.acquire(new Runnable() {

    @Override
    public void run() {
      if (promise.isDone()) {
        lock.release();
        freePubSubLock.release();
        return;
      }

      // 从队列中取头部元素
      PubSubConnectionEntry freeEntry = freePubSubConnections.peek();
      if (freeEntry == null) {
        // 第一次肯定是没有的需要建立
        connect(codec, channelName, promise, type, lock, listeners);
        return;
      }

      // 如果存在则尝试获取,如果remainFreeAmount小于0则抛出异常终止了。
      int remainFreeAmount = freeEntry.tryAcquire();
      if (remainFreeAmount == -1) {
        throw new IllegalStateException();
      }

      PubSubConnectionEntry oldEntry = name2PubSubConnection.putIfAbsent(channelName, freeEntry);
      if (oldEntry != null) {
        freeEntry.release();
        freePubSubLock.release();

        addListeners(channelName, promise, type, lock, oldEntry, listeners);
        return;
      }

      // 如果remainFreeAmount=0, 则从队列中移除
      if (remainFreeAmount == 0) {
        freePubSubConnections.poll();
      }
      freePubSubLock.release();

      // 增加监听
      RFuture<Void> subscribeFuture = addListeners(channelName, promise, type, lock, freeEntry, listeners);

      ChannelFuture future;
      if (PubSubType.PSUBSCRIBE == type) {
        future = freeEntry.psubscribe(codec, channelName);
      } else {
        future = freeEntry.subscribe(codec, channelName);
      }

      future.addListener(new ChannelFutureListener() {
        @Override
        public void operationComplete(ChannelFuture future) throws Exception {
          if (!future.isSuccess()) {
            if (!promise.isDone()) {
              subscribeFuture.cancel(false);
            }
            return;
          }

          connectionManager.newTimeout(new TimerTask() {
            @Override
            public void run(Timeout timeout) throws Exception {
              subscribeFuture.cancel(false);
            }
          }, config.getTimeout(), TimeUnit.MILLISECONDS);
        }
      });
    }

  });
}


private void connect(Codec codec, ChannelName channelName, RPromise<PubSubConnectionEntry> promise, PubSubType type, AsyncSemaphore lock, RedisPubSubListener<?>... listeners) {
  // 根据channelName计算出slot获取PubSubConnection
  int slot = connectionManager.calcSlot(channelName.getName());
  RFuture<RedisPubSubConnection> connFuture = nextPubSubConnection(slot);
  promise.onComplete((res, e) -> {
    if (e != null) {
      ((RPromise<RedisPubSubConnection>) connFuture).tryFailure(e);
    }
  });


  connFuture.onComplete((conn, e) -> {
    if (e != null) {
      freePubSubLock.release();
      lock.release();
      promise.tryFailure(e);
      return;
    }

    // 这里会从配置中读取subscriptionsPerConnection
    PubSubConnectionEntry entry = new PubSubConnectionEntry(conn, config.getSubscriptionsPerConnection());
    // 每获取一次,subscriptionsPerConnection就会减直到为0
    int remainFreeAmount = entry.tryAcquire();

    // 如果旧的存在,则将现有的entry释放,然后将listeners加入到oldEntry中
    PubSubConnectionEntry oldEntry = name2PubSubConnection.putIfAbsent(channelName, entry);
    if (oldEntry != null) {
      releaseSubscribeConnection(slot, entry);

      freePubSubLock.release();

      addListeners(channelName, promise, type, lock, oldEntry, listeners);
      return;
    }


    if (remainFreeAmount > 0) {
      // 加入到队列中
      freePubSubConnections.add(entry);
    }
    freePubSubLock.release();

    RFuture<Void> subscribeFuture = addListeners(channelName, promise, type, lock, entry, listeners);

    // 这里真正的进行订阅(底层与redis交互)
    ChannelFuture future;
    if (PubSubType.PSUBSCRIBE == type) {
      future = entry.psubscribe(codec, channelName);
    } else {
      future = entry.subscribe(codec, channelName);
    }

    future.addListener(new ChannelFutureListener() {
      @Override
      public void operationComplete(ChannelFuture future) throws Exception {
        if (!future.isSuccess()) {
          if (!promise.isDone()) {
            subscribeFuture.cancel(false);
          }
          return;
        }

        connectionManager.newTimeout(new TimerTask() {
          @Override
          public void run(Timeout timeout) throws Exception {
            subscribeFuture.cancel(false);
          }
        }, config.getTimeout(), TimeUnit.MILLISECONDS);
      }
    });
  });
}

PubSubConnectionEntry#tryAcquire方法, subscriptionsPerConnection代表了每个连接的最大订阅数。当tryAcqcurie的时候会减少这个数量:

public int tryAcquire() {
while (true) {
int value = subscribedChannelsAmount.get();
if (value == 0) {
return -1;
}

if (subscribedChannelsAmount.compareAndSet(value, value - 1)) {
return value - 1;
}
}
}

梳理上述逻辑:

1、还是进行重复判断, 根据channelName从name2PubSubConnection中获取,看是否存在已经订阅:PubSubConnectionEntry; 如果存在直接把新的listener加入到PubSubConnectionEntry。
2、从队列freePubSubConnections中取公用的PubSubConnectionEntry, 如果没有就进入connect()方法

2.1 会根据subscriptionsPerConnection创建PubSubConnectionEntry, 然后调用其tryAcquire()方法 - 每调用一次就会减1
2.2 将新的PubSubConnectionEntry放入全局的name2PubSubConnection, 方便后续重复使用;
2.3 同时也将PubSubConnectionEntry放入队列freePubSubConnections中。- remainFreeAmount > 0
2.4 后面就是进行底层的subscribe和addListener

3、如果已经存在PubSubConnectionEntry,则利用已有的PubSubConnectionEntry进行tryAcquire;
4、如果remainFreeAmount < 0 会抛出IllegalStateException异常;如果remainFreeAmount=0,则会将其从队列中移除, 那么后续请求会重新获取一个可用的连接
5、最后也是进行底层的subscribe和addListener;

三 总结

根因: 从上面代码分析, 导致问题的根因是因为PublishSubscribeService 会使用公共队列中的freePubSubConnections, 如果同一个key一次性请求超过subscriptionsPerConnection它的默认值5时,remainFreeAmount就可能出现-1的情况, 那么就会导致commandExecutor.syncSubscription(future)中等待超时,也就抛出如上异常Subscribe timeout: (7500ms). Increase 'subscriptionsPerConnection' and/or 'subscriptionConnectionPoolSize' parameters.

解决方法: 在初始化Redisson可以可指定这个配置项的值。

相关参数的解释以及默认值请参考官网:https://github.com/redisson/redisson/wiki/2.-Configuration#23-common-settings

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