Laravel 模型使用软删除-左连接查询-表起别名示例

2020-09-03 11:57:55

事情是这样的,有天写了一个左连接查询,由于表名太长,所以分别给起个别名,代码如下:

public function detail(){  $result = TakeOrderModel::query()    ->from('take_order as order')    ->leftJoin('take_order_detail as detail', 'order.id', '=', 'detail.take_order_id')    ->get();  dd($result);}

执行后,报错 Column not found: 1054 Unknown column take_order.delete_time。

查看解决办法的,直接看底部

SQL:

select * from take_order as orderleft join take_order_detail as detailon order.take_order_id = detail.take_order_idwhere take_order.delete_time is null

显而易见:软删除查询条件的表名是全名,所以报错了。

分析

软删除作用域 SoftDeletingScope 源码:

/** * Apply the scope to a given Eloquent query builder. * * @param IlluminateDatabaseEloquentBuilder $builder * @param IlluminateDatabaseEloquentModel $model * @return void */public function apply(Builder $builder, Model $model){  $builder->whereNull($model->getQualifiedDeletedAtColumn());}

查看 getQualifiedDeletedAtColumn 源码:

/** * Get the fully qualified "deleted at" column. * * @return string */public function getQualifiedDeletedAtColumn(){  return $this->qualifyColumn($this->getDeletedAtColumn());}

查看 qualifyColumn 源码:

/** * Qualify the given column name by the model's table. * * @param string $column * @return string */public function qualifyColumn($column){  return $this->model->qualifyColumn($column);}

查看 qualifyColumn 源码:

/** * Qualify the given column name by the model's table. * * @param string $column * @return string */public function qualifyColumn($column){  if (Str::contains($column, '.')) {    return $column;  }  return $this->getTable().'.'.$column;}

以上可知: $this->getTable().'.'.$column 即为软删除条件的字段名。

解决办法

代码改成下面这样,加一行 setTable 设置表名,就可以了。

$result = (new TakeOrderModel())    ->setTable('order')    ->from('take_order as order')    ->leftJoin('take_order_detail as detail', 'order.take_order_id', '=', 'detail.take_order_id')    ->get();

因为写代码时要指定具体的查询 columns ,有时表名真的太长,看着很不舒服,所以有此尝试。嗯,9 点了,下班。

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