Node.js中如何合并两个复杂对象详解

2020-06-17 07:00:39易采站长站整理

{
def[i][x] = mergeObjs(def[i][x],newobj);
}
else {
newobjs.push(newobj);
}
}

for(var x= 0, l = newobjs.length; x<l; x++) {
def[i].push(newobjs[x]);
}
}
else {
for(var x=0; x < obj[i].length; x++)
{
var idxObj = obj[i][x];
if(def[i].indexOf(idxObj) === -1) {
def[i].push(idxObj);
}
}
}
}
else
{
def[i] = obj[i];
}
}
return def;}

将上述代码稍作改进,我们可以实现在合并过程中将Number类型的值自动相加。


function merge(def, obj) {
if (!obj) {
return def;
}
else if (!def) {
return obj;
}

for (var i in obj) {
// if its an object
if (obj[i] != null && obj[i].constructor == Object)
{
def[i] = merge(def[i], obj[i]);
}
// if its an array, simple values need to be joined. Object values need to be re-merged.
else if(obj[i] != null && (obj[i] instanceof Array) && obj[i].length > 0)
{
// test to see if the first element is an object or not so we know the type of array we're dealing with.
if(obj[i][0].constructor == Object)
{
var newobjs = [];
// create an index of all the existing object IDs for quick access. There is no way to know how many items will be in the arrays.
var objids = {}
for(var x= 0, l= def[i].length ; x < l; x++ )
{
objids[def[i][x].id] = x;
}

// now walk through the objects in the new array
// if the ID exists, then merge the objects.
// if the ID does not exist, push to the end of the def array
for(var x= 0, l= obj[i].length; x < l; x++)
{
var newobj = obj[i][x];
if(objids[newobj.id] !== undefined)
{
def[i][x] = merge(def[i][x],newobj);
}
else {
newobjs.push(newobj);
}
}

for(var x= 0, l = newobjs.length; x<l; x++) {
def[i].push(newobjs[x]);
}
}
else {
for(var x=0; x < obj[i].length; x++)
{
var idxObj = obj[i][x];
if(def[i].indexOf(idxObj) === -1) {
def[i].push(idxObj);
}
}
}
}
else
{
if (isNaN(obj[i]) || i.indexOf('_key') > -1){
def[i] = obj[i];
}
else{
def[i] += obj[i];
}
}
}
return def;
}

例如有以下两个对象:


var data1 = {
"_id" : "577327c544bd90be508b46cc",
"channelId_info" : [
{
"channelId_key" : "0",
"secondLevel_group" : [
{
"secondLevel_key" : "568cc36c44bd90625a045c60",
"sender_group" : [
{
"sender_key" : "577327c544bd90be508b46cd",