求A2-A1,求出移动的弧度
this.tranformRadian = this.curRadian - this.preRadian求出最后box的旋转角度,this.getRotate(target)是js中获取某dom元素的旋转角度的方法(粘贴过来的,亲测好使)
this.angle = this.getRotate(target) + Math.round(this.tranformRadian * 180 / Math.PI)
this.preRadian = this.curRadian //鼠标移动的每一下都计算这个角度,所以每一下移动前的弧度值都上一次移动后的弧度值计算旋转后box每个点的坐标,根据余弦公式,传入:旋转前每点坐标,旋转中心坐标和旋转角度
let disAngle = this.angle - this.initAngle
this.rightBottomPoint = this.getRotatedPoint(this.initRightBottomPoint, this.centerPos, disAngle)
this.rightTopPoint = this.getRotatedPoint(this.initRightTopPoint, this.centerPos, disAngle)
this.leftTopPoint = this.getRotatedPoint(this.initLeftTopPoint, this.centerPos, disAngle)
this.leftBottomPoint = this.getRotatedPoint(this.initLeftBottomPoint, this.centerPos, disAngle)
this.leftMiddlePoint = this.getRotatedPoint(this.initLeftMiddlePoint, this.centerPos, disAngle)
this.rightMiddlePoint = this.getRotatedPoint(this.initRightMiddlePoint, this.centerPos, disAngle)
this.topMiddlePoint = this.getRotatedPoint(this.initTopMiddlePoint, this.centerPos, disAngle)
this.bottomMiddlePoint = this.getRotatedPoint(this.initBottomMiddlePoint, this.centerPos, disAngle)
沿着一个方向拉升操作。
沿着一个角缩放操作。 这两个操作,主要参考了一个大佬的拖拽思想实现的 github wiki地址
优化,mousemove事件添加节流函数
function throttle(fn, interval) {
let canRun = true;
return function () {
if (!canRun) return;
canRun = false;
setTimeout(() => {
fn.apply(this, arguments);
canRun = true;
}, interval);
};
}
let that = this
document.addEventListener('mousemove', throttle(function (e) {
e.preventDefault && e.preventDefault()
that.moveChange(e, that.targetObj)
}, 10))以上所述是小编给大家介绍的基于javascript的拖拽类封装详解整合,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对软件开发网网站的支持!










