jquery ajax提交表单数据的两种方式

2020-05-23 06:01:18易采站长站整理

<input type=”reset” class=”button” value=”还原” />
</td>
</tr>
</table>
<span id=”Tip”></span>
</div>
</form>
</body>

后台代码:

protected void Page_Load(object sender, EventArgs e)
{
{
if (Request.QueryString[“flag”] != null && Request.QueryString[“flag”].ToString() == “do”)
{
Pxt.Logic.DBRec.ReturnVisit bll = new Pxt.Logic.DBRec.ReturnVisit();
if (bll.Add(model(0)) > 0)
{
Response.Write(“操作成功!”);
Response.End();
}
}
}
}
/**//// <summary>
/// 根据不同需要,设定模型->获取模型
/// </summary>
/// <param name=”id”>ID值</param>
/// <returns></returns>
private Pxt.Model.DBRec.ReturnVisit model(int id)
{
//获取表单值
string F_CorpName = Request.Form[“txtF_CorpName”].ToString();
string F_ReturnVisitTitle = Request.Form[“txtF_ReturnVisitTitle”].ToString();
string F_ContractPerson = Request.Form[“txtF_ContractPerson”].ToString();
string F_ContractPersonPosition = Request.Form[“txtF_ContractPersonPosition”].ToString();
string F_ContractPhone = Request.Form[“txtF_ContractPhone”].ToString();
DateTime F_ReturnVisitDate = DateTime.Parse(Request.Form[“txtF_ReturnVisitDate”].ToString());
string F_ReturnVisitContent = Request.Form[“txtF_ReturnVisitContent”].ToString();
string F_ReturnVisitFile = Request.Form[“txtF_ReturnVisitFile”].ToString();
string Refer = Session[“username”].ToString();
DateTime DoTime = DateTime.Now.Date;
Pxt.Model.DBRec.ReturnVisit model = new Pxt.Model.DBRec.ReturnVisit();
if (id > 0)//修改记录,否则表示增加记录
{
model.ID = id;
}
model.F_CorpName = F_CorpName;
model.F_ReturnVisitTitle = F_ReturnVisitTitle;
model.F_ContractPerson = F_ContractPerson;
model.F_ContractPersonPosition = F_ContractPersonPosition;
model.F_ContractPhone = F_ContractPhone;
model.F_ReturnVisitDate = F_ReturnVisitDate;
model.F_ReturnVisitContent = F_ReturnVisitContent;
model.F_ReturnVisitFile = F_ReturnVisitFile;
model.Refer = Refer;
model.DoTime = DoTime;
return model;
}

注:Jquery.form是Jquery用于帮助操作表单的一个插件,具体的去网上看看教程!