这里直接打印了slice的指针值，因为slice是引用类型，所以指针值都是相同的，我们换成打印slice的地址看下
func rmLast(a []int) {
fmt.Printf("[rmlast] the address of a is %p", &a)
a = a[:len(a)-1]
fmt.Printf("[rmlast] after remove, the address of a is %p", &a)
}
func main() {
xyz := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}
fmt.Printf("[main] the address of xyz is %pn", &xyz)
rmLast(xyz)
fmt.Printf("[main] after remove, the address of xyz is %pn", &xyz)
fmt.Printf("%v", xyz) //[1 2 3 4 5 6 7 8 9]
}
结果：
[main] the address of xyz is 0xc20801e1e0
[rmlast] the address of a is 0xc20801e200
[rmlast] after remove, the address of a is 0xc20801e200
[main] after remove, the address of xyz is 0xc20801e1e0
[1 2 3 4 5 6 7 8 9]
这次可以看到slice作为函数参数传入函数时，实际上也是拷贝了一份slice，因为slice本身是个指针，所以从现象来看，slice是引用类型
总结
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