Go语言实现的最简单数独解法

2020-01-28 11:25:58于丽

soduku.go


package main
import (
    "fmt"
)
type node []int
var sudokuMay [9][9]node
var Sudoku = [9][9]int{
    {0, 0, 0, 0, 0, 0, 8, 0, 0},
    {0, 8, 2, 4, 0, 0, 0, 0, 0},
    {1, 9, 0, 0, 6, 3, 0, 0, 0},
    {0, 5, 0, 0, 8, 0, 7, 0, 0},
    {6, 7, 8, 2, 0, 9, 1, 4, 3},
    {0, 0, 3, 0, 4, 0, 0, 8, 0},
    {0, 0, 0, 6, 2, 0, 0, 9, 4},
    {0, 0, 0, 0, 0, 5, 6, 1, 0},
    {0, 0, 0, 6, 0, 0, 0, 0, 0}}
func main() {
    n := inited(Sudoku)
    SudokuSure, _ := sure(sudokuMay)
    for n > 0 {
        n = Subinit(SudokuSure)
        // Output(sudokuMay)
        // fmt.Println(n)
        SudokuSure, _ = sure(sudokuMay)
    }
    Output(sudokuMay)
    fmt.Println(isEnable(sudokuMay))
    // test()
}
func isEnable(tn [9][9]node) bool {
    for i := 0; i < 9; i++ {
        for j := 0; j < 9; j++ {
            if len(tn[i][j]) == 0 {
                return false
            }
        }
    }
    return true
}
func sure(may [9][9]node) (sure [9][9]int, n int) {
    n = 0
    for i := 0; i < 9; i++ {
        for j := 0; j < 9; j++ {
            if len(may[i][j]) == 1 {
                sure[i][j] = may[i][j][0]
                n++
            } else {
                sure[i][j] = 0
            }
        }
    }
    return
}
func test() {
    i, j := 1, 3
    fmt.Println(Sudoku[i][j])
    for k := ((i / 3) * 3); k < ((i/3)*3)+3; k++ {
        for l := ((j / 3) * 3); l < ((j/3)*3)+3; l++ {