C++ 中＂emplace_back＂ 与 ＂push_back＂ 的区别

 C++ 中"emplace_back" 与 "push_back" 的区别

emplace_back和push_back都是向容器内添加数据.

对于在容器中添加类的对象时, 相比于push_back,emplace_back可以避免额外类的复制和移动操作.

"emplace_back avoids the extra copy or move operation required when using push_back."

参见: http://www.easck.com/w/cpp/container/vector/emplace_back

注意下面代码中的emplace_back和push_back的添加方式(VS2012下编译通过):

#include <vector> 
#include <string> 
#include <iostream> 
 
struct President 
{ 
  std::string name; 
  std::string country; 
  int year; 
 
  President(std::string p_name, std::string p_country, int p_year) 
    : name(std::move(p_name)), country(std::move(p_country)), year(p_year) 
  { 
    std::cout << "I am being constructed.n"; 
  } 
  President(President&& other) 
    : name(std::move(other.name)), country(std::move(other.country)), year(other.year) 
  { 
    std::cout << "I am being moved.n"; 
  } 
  President& operator=(const President& other); 
}; 
 
int main() 
{ 
  std::vector<President> elections; 
  std::cout << "emplace_back:n"; 
  elections.emplace_back("Nelson Mandela", "South Africa", 1994); //没有类的创建 
 
  std::vector<President> reElections; 
  std::cout << "npush_back:n"; 
  reElections.push_back(President("Franklin Delano Roosevelt", "the USA", 1936)); 
 
  std::cout << "nContents:n"; 
  for (President const& president: elections) { 
    std::cout << president.name << " was elected president of " 
      << president.country << " in " << president.year << ".n"; 
  } 
  for (President const& president: reElections) { 
    std::cout << president.name << " was re-elected president of " 
      << president.country << " in " << president.year << ".n"; 
  } 
}