C语言实现的程序员老黄历实例

2020-01-06 13:19:41刘景俊
  • {"在妹子面前吹牛", "改善你矮穷挫的形象","会被识破", },  {"撸管", "避免缓冲区溢出","强撸灰飞烟灭", }, 
  • {"浏览成人网站", "重拾对生活的信心","你会心神不宁", },  {"上微博", "今天发生的事不能错过","会看到令人心情不好的事", }, 
  • {"上AB站", "还需要理由吗?","满屏的兄贵我会说出来?", }  }; 
  • printf("|-------------------------------------|n");  if(isWeekend(p))  
  • printf("| 宜: n| %2sn| %sn",activities[19+randNum%8][0],activities[randNum%27][1]);  else 
  • printf("| 宜: n| %2sn| %sn",activities[randNum%17][0],activities[randNum%27][1]);  printf("|-------------------------------------|n");  
  • printf("|-------------------------------------|n");   if(isWeekend(p)) 
  • printf("| 不宜:n| %sn| %sn",activities[19+randNum1%8][0],activities[randNum1%27][2]);  else 
  • printf("| 不宜:n| %sn| %sn",activities[randNum1%17][0],activities[randNum1%27][2]);  printf("|-------------------------------------|n");  
  • /*座位朝向*/  char *directions[8]= {"北方","东北方","东方","东南方","南方","西南方","西方","西北方"}; 
  • printf("|-------------------------------------|n");  printf("| 座位朝向:面向 %s 写程序,BUG 最少.n",directions[randNum%8]); 
  • /*今日宜饮*/  char *drinks[14] = {"水","茶","红茶","绿茶","咖啡","奶茶","可乐","牛奶","豆奶","果汁","果味汽水","苏打水","运动饮料","酸奶","酒"};  
  • printf("|-------------------------------------|n");  printf("| 今日宜饮:%s,%sn",drinks[randNum%14],drinks[randNum1%14]); 
  • /*女神亲近指数*/  int ambiguous = randNum%10; 
  • printf("|-------------------------------------|n");  if(10==ambiguous) 
  • printf("| 亲近指数为10,上吧,骚年!n");  else