C#解析Lrc歌词文件过程详解

一行代码：Lrc lrc= Lrc.InitLrc("test.lrc"); 

我将分离好的歌词放入了Dictionary<double, string>里，当然也可以直接用数组存，格式就要看实际的用途了，把这些都交给TimeSpan来做吧。 
测试: 

很久以前有人提出了这个问题：一行歌词里面有多个时间会报错，这么久了也没见人把好的方案提供出来，今天我花了点时间，修改了下，下面是获取歌词方法 

/// <summary>
  /// 获得歌词信息
  /// </summary>
  /// <param name="LrcPath">歌词路径</param>
  /// <returns>返回歌词信息(Lrc实例)</returns>
  public static Lrc InitLrc(string LrcPath)
  {
   Lrc lrc = new Lrc();
   Dictionary<double, string> dicword = new Dictionary<double, string>();
   using (FileStream fs = new FileStream(LrcPath, FileMode.Open, FileAccess.Read, FileShare.Read))
   {
    string line;
    using (StreamReader sr = new StreamReader(fs, Encoding.Default))
    {
     while ((line = sr.ReadLine()) != null)
     {
      if (line.StartsWith("[ti:"))
      {
       lrc.Title = SplitInfo(line);
      }
      else if (line.StartsWith("[ar:"))
      {
       lrc.Artist = SplitInfo(line);
      }
      else if (line.StartsWith("[al:"))
      {
       lrc.Album = SplitInfo(line);
      }
      else if (line.StartsWith("[by:"))
      {
       lrc.LrcBy = SplitInfo(line);
      }
      else if (line.StartsWith("[offset:"))
      {
       lrc.Offset = SplitInfo(line);
      }
      else
      {
       try
       {
        Regex regexword = new Regex(@".*](.*)");
        Match mcw = regexword.Match(line);
        string word = mcw.Groups[1].Value;
        Regex regextime = new Regex(@"[([0-9.:]*)]", RegexOptions.Compiled);
        MatchCollection mct = regextime.Matches(line);
        foreach (Match item in mct)
        {
         double time = TimeSpan.Parse("00:" + item.Groups[1].Value).TotalSeconds;
         dicword.Add(time, word);
        }
       }
       catch
       {
        continue;
       }
      }
     }
    }
   }
   lrc.LrcWord = dicword.OrderBy(t => t.Key).ToDictionary(t => t.Key, p => p.Value);
   return lrc;
  }