所以：入列时rear++的操作，应该稍做修正，当rear到数组下标最大值时，让它置0，以便能循环利用 (见后面的代码)
另外还有一个问题：最开始时front与rear都为-1，即front==rear时表示队列为空，改成循环以后，有可能会出现rear在循环过程中碰到front的情况，即真正意义的上"满"状态，这时rear也同样等于front，这样就无法单纯的用rear==front来判断是满，还是空？这时可以浪费一个元素的位置，认为当rear+1==front时，队列就已经满了，虽然牺牲了一个元素的空间，但却换来了逻辑的正确性，还是值得的。
完整实现如下：
using System;
using System.Text;
namespace 栈与队列
{
/// <summary>
/// 循环顺序队列
/// </summary>
/// <typeparam name="T"></typeparam>
public class CSeqQueue<T>:IQueue<T>
{
private int maxsize;
private T[] data;
private int front;
private int rear;
public CSeqQueue(int size)
{
data = new T[size];
maxsize = size;
front = rear = -1;
}
public int Count()
{
if (rear > front)
{
return rear - front;
}
else
{
return (rear - front + maxsize) % maxsize;
}
}
public void Clear()
{
front = rear = -1;
}
public bool IsEmpty()
{
return front == rear;
}
public bool IsFull()
{
if (front != -1) //如果已经有元素出队过
{
return (rear + 1) % maxsize == front;//为了区分与IsEmpty的区别，有元素出队过以后，就只有浪费一个位置来保持逻辑正确性.
}
else
{
return rear == maxsize - 1;
}
}
public void Enqueue(T item)
{
if (IsFull())
{
Console.WriteLine("Queue is full");
return;
}
if (rear == maxsize - 1) //如果rear到头了，则循环重来（即解决伪满问题）
{
rear = 0;
}
else
{
rear++;
}
data[rear] = item;
}
public T Dequeue()
{
if (IsEmpty())
{
Console.WriteLine("Queue is empty");
return default(T);
}
if (front == maxsize - 1) //如果front到头了，则重新置0
{
front = 0;
}
else
{
front++;
}
return data[front];
}
public T Peek()
{
if (IsEmpty())
{
Console.WriteLine("Queue is empty!");
return default(T);
}
return data[(front + 1) % maxsize];
}
public override string ToString()
{
if (IsEmpty()) { return "queue is empty."; }
StringBuilder sb = new StringBuilder();
if (rear > front)
{
for (int i = front + 1; i <= rear; i++)
{
sb.Append(this.data[i].ToString() + ",");
}
}
else
{
for (int i = front + 1; i < maxsize; i++)
{
sb.Append(this.data[i].ToString() + ",");
}
for (int i = 0; i <= rear; i++)
{
sb.Append(this.data[i].ToString() + ",");
}
}
return "front = " + this.front + " t rear = " + this.rear + "t count = " + this.Count() + "t data = " + sb.ToString().Trim(',');
}
}
}
