linux控制台下实现2048小游戏

2019-10-14 10:57:09于丽

    printf("    ");
    printf("33[%d;%dH",3+line*4,2+row*5);
    if(arr[line][row]!=0)
        for(i=0;i<4;i++)
        {
            if(p[i]=='0'&&i<1)
                printf(" ");
            else
            if(p[i]!='0')
            {
                printf("33[%dm",NUM_COLOR);
                printf("%c",p[i]);
                printf("33[0m");
            }
        }
    else
        if(arr[line][row]==0)
        printf("    ");
}
int print_num()
{
    int i,j;
    for(i=0;i<4;i++)
        for(j=0;j<4;j++)
    put_to(i,j);
}
print_score()
{
    int x,y;
    printf("33[19;9H");
    printf("%d",score);
}
int ran_appear()
{
    int line,row;
    int i=0;
    int j=0;
    int x,y;
    int arr1[16][2]={0};
    if(print_appear_flag==1)
        return 0;
    for(x=0;x<4;x++)
        for(y=0;y<4;y++)
        {
            if(arr[x][y]==0)
            {
                arr1[i][0]=x;
                arr1[i][1]=y;
                i++;
            }
        }
    srand(time(NULL));
    j=rand()%i;
    if(rand()%2==0)
      {
        arr[arr1[j][0]][arr1[j][1]]=4;