python实现监控windows服务并自动启动服务示例

AppXml.py

#!/usr/bin/env python
#-*- encoding:utf-8 -*-

"""
XML操作封装
"""

import os.path;
import logging;
import xml.etree.ElementTree as ElementTree;

class XmlNodeValue(object):
    STRING = 1;
    INT = 2;
    FLOAT = 3;
    BOOL = 4;

class XmlNodeMap(object):
    ATTR = 1;
    TEXT = 2;
    NODE = 3;

class XmlNode(object):

    def __init__(self,currentNode=None,rootNode=None):
        self.currentNode = currentNode;
        self.rootNode = rootNode;

    # 加载XML文件
    def LoadFile(self,path):
        if os.path.isabs(path): path = os.path.abspath(path);
        flag = False;
        try:
            self.rootNode = ElementTree.parse(path);
            if self.rootNode is not None: flag = True;
            self.currentNode = self.rootNode;
        except Exception,e:
            logging.error("XML文件加载失败");
            logging.error(e.__str__());
        return flag;

    # 加载XML内容
    def LoadString(self,data):
        if data is None or len(data.strip())==0: return False;
        flag = False;
        try:
            self.rootNode = ElementTree.fromstring(data);
            if self.rootNode is not None: flag = True;
            self.currentNode = self.rootNode;
        except Exception,e:
            logging.error("XML内容加载失败");
            logging.error(e.__str__());
        return flag;

    #  检查数据是否载入正确
    def IsLoad(self):
        return self.currentNode is not None and self.rootNode is not None;

    # 返回根节点对象
    def GetRoot(self):
        return XmlNode(self.rootNode,self.rootNode);