python实现的阳历转阴历（农历）算法

                break

            nTheDate = nTheDate – 29 – nBit
            n = n – 1

        if nIsEnd != 0:
            break
        m = m + 1

    wCurYear = 1921 + m
    wCurMonth = k – n + 1
    wCurDay = int(math.floor(nTheDate))
    if k == 12:
        if wCurMonth == wNongliData[m] / 65536 + 1:
            wCurMonth = 1 – wCurMonth
        elif wCurMonth > wNongliData[m] / 65536 + 1:
            wCurMonth = wCurMonth – 1

    print '阳历', st["year"], st["mon"], st["day"]
    print '农历', wCurYear, wCurMonth, wCurDay
    #–生成农历天干、地支、属相 ==> wNongli–
    szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]
    szShuXiang = cShuXiang[(((wCurYear - 4) % 60) % 12) + 1]
    zNongli = szShuXiang + '(' + cTianGan[(((wCurYear - 4) % 60) % 10)] + cDiZhi[(((wCurYear - 4) % 60) % 12)] + ')年'
    #–szNongli,"%s(%s%s)年",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]);

    #–生成农历月、日 ==> wNongliDay–*/
    if wCurMonth < 1:
        szNongliDay =  "闰" + cMonName[(-1 * wCurMonth)]
    else:
        szNongliDay = cMonName[wCurMonth]

    szNongliDay =  szNongliDay + "月" + cDayName[wCurDay]
    print szNongliDay
    #return szNongli .. szNongliDay

def main():
    st = {"year": 1989, "mon": 8, "day": 1}
    GetDayOf(st)
    st1 = {"year": 2013, "mon": 10, "day": 7}
    GetDayOf(st1)
    st1 = {"year": 2013, "mon": 10, "day": 1}
    GetDayOf(st1)
    #print("" .. GetDayOf(st))
main()

数据基本上正确了，根据自己的需要改一改程序就可以了。以后有时间在改好一点的。