python数据结构之二叉树的统计与转换实例

2019-10-06 16:02:41于海丽

        if root.left is 0 and root.right is 0:
            res += 1
            return res
        if root.left is not 0:
            res += self.__count_leaf_node(root.left)
        if root.right is not 0:
            res += self.__count_leaf_node(root.right)
        return res

    def getbranchcount(self):
        ''' 获取二叉树分支节点数 '''
        return self.__get_branch_node(self.root)

    def __get_branch_node(self, root):
        if root is 0:
            return 0
        if root.left is 0 and root.right is 0:
            return 0
        else:
            return 1 + self.__get_branch_node(root.left) + self.__get_branch_node(root.right)

    def replacelem(self):
        ''' 二叉树所有结点的左右子树相互交换 '''
        self.__replace_element(self.root)

    def __replace_element(self, root):
        if root is 0:
            return
        root.left, root.right = root.right, root.left
        self.__replace_element(root.left)
        self.__replace_element(root.right)

node1 = TreeNode(data=1)
node2 = TreeNode(node1, 0, 2)
node3 = TreeNode(data=3)
node4 = TreeNode(data=4)
node5 = TreeNode(node3, node4, 5)
node6 = TreeNode(node2, node5, 6)
node7 = TreeNode(node6, 0, 7)
node8 = TreeNode(data=8)
root = TreeNode(node7, node8, 'root')

    
bt = BinaryTree(root)

print u'''

生成的二叉树

------------------------
         root
      7        8
    6
  2   5
1    3 4

-------------------------

'''