此外我还有一个需求，是把英文名[空格]中文名分成英文姓、英文名、中文姓、中文名。
首先我需要能把英文和中文分割开，我的办法是用正则匹配，按照常见中英文字符在unicode的范围来套。匹配英文和中文的正则pattern如下：
# regex pattern matching all ascii characters
asciiPattern = ur'[%s]+' % ''.join(chr(i) for i in range(32, 127))
# regex pattern matching all common Chinese characters and seporators
chinesePattern = ur'[u4e00-u9fff. %s]+' % (''.join(seps))
英文就用ASCII可打印字符的范围替代，常见中文字符的范围是u4e00-u9fff，那个seps是前面提到过的超出GBK范围的一些字符。 除了简单的分割，我还需要处理只有中文名没有英文名、只有英文名没有中文名等情况，判断逻辑如下：
def split_name(name):
"""Split [English name, Chinese name].
If one of them is missing, None will be returned instead.
Usage:
engName, chName = split_name(name)
"""
matches = re.match('(%s) (%s)' % (asciiPattern, chinesePattern), name)
if matches: # English name + Chinese name
return matches.group(1).strip(), matches.group(2).strip()
else:
matches = re.findall('(%s)' % (chinesePattern), name)
matches = ''.join(matches).strip()
if matches: # Chinese name only
return None, matches
else: # English name only
matches = re.findall('(%s)' % (asciiPattern), name)
return ''.join(matches).strip(), None
得到了中文名之后，我需要分割成姓和名，因为任务要求不需要把姓名分割得很明确，我就按照常见的中文名姓名分割方式来分——两个字or三个字的第一个字是姓，四个字的前两个字是姓，名字带分隔符的（少数民族名字）分隔符前是姓（这里用到了前面的get_clean_ch_string函数来移除分隔符），名字再长一些又不带分割符的，假设整个字符串都是名字。（注意英语的first name 指的是名，last name指的是姓，2333）
def split_ch_name(chName):
"""Split the Chinese name into first name and last name.
* If the name is XY or XYZ, X will be returned as the last name.
* If the name is WXYZ, WX will be returned as the last name.
* If the name is ...WXYZ, the whole name will be returned
as the last name.
* If the name is ..ABC * XYZ..., the part before the seperator
will be returned as the last name.
Usage:
chFirstName, chLastName = split_ch_name(chName)
"""
if len(chName) < 4: # XY or XYZ
chLastName = chName[0]
chFirstName = chName[1:]
elif len(chName) == 4: # WXYZ
chLastName = chName[:2]
chFirstName = chName[2:]
else: # longer
cleanName = get_clean_ch_string(chName)
nameParts = cleanName.split()
print u' '.join(nameParts)
if len(nameParts) < 2: # ...WXYZ
return None, nameParts[0]
chLastName, chFirstName = nameParts[:2] # ..ABC * XYZ...
return chFirstName, chLastName
