Linux shell脚本编程if语句的使用方法(条件判断)

2019-09-23 09:44:17于丽

  -eq  -ne  -lt  -nt只能用于整数,不适用于字符串,字符串等于用赋值号=
[macg@machome ~]$ vi test.sh
echo -n "input your choice:"
read var
if  [ $var -eq "yes" ]
then
echo $var
fi
[macg@machome ~]$ sh -x test.sh
input your choice:
y
test.sh: line 3: test: y: integer expression_r_r_r expected
                       期望整数形式,即-eq不支持字符串     =放在别的地方是赋值,放在if [ ] 里就是字符串等于,shell里面没有==的,那是c语言的等于
   无空格的字符串,可以加" ",也可以不加

[macg@machome ~]$ vi test.sh
echo "input a:"
read a
echo "input is $a"
if [ $a = 123 ] ; then
echo equal123
fi
[macg@machome ~]$ sh test.sh
input a:
123
input is 123
equal123      = 作为等于时,其两边都必须加空格,否则失效
等号也是操作符,必须和其他变量,关键字,用空格格开 (等号做赋值号时正好相反,两边不能有空格)

[macg@machome ~]$ vi test.sh echo "input your choice:"
read var
if [ $var="yes" ]
then
echo $var
echo "input is correct"
else
echo $var
echo "input error"
fi
[macg@machome ~]$ vi test.sh echo "input your choice:"
read var
if [ $var = "yes" ]   在等号两边加空格
then
echo $var
echo "input is correct"
else
echo $var
echo "input error"
fi
[macg@machome ~]$ sh test.sh
input your choice:
y
y
input is correct
[macg@machome ~]$ sh test.sh
input your choice:

n
input is correct
输错了也走then,都走then,为什么?
因为if把$var="yes"连读成一个变量,而此变量为空,返回1,则走else   [macg@machome ~]$ sh test.sh
input your choice:
y
y
input error
[macg@machome ~]$ sh test.sh
input your choice:
no                      
no
input error
一切正常     If  [  $ANS  ]     等价于  if [ -n $ANS ]
      如果字符串变量非空(then) , 空(else)

echo "input your choice:"
read ANS if [ $ANS ]
then
echo no empty
else
echo empth
fi
[macg@machome ~]$ sh test.sh
input your choice:                       回车

empth                                    说明“回车”就是空串
[macg@machome ~]$ sh test.sh
input your choice:
34
no empty