bash shell命令行选项与修传入参数处理

2019-09-23 09:40:46王振洲

# mkdir -f #不成功,因为-f会被mkdir当作选项来解析,这时就可以使用
# mkdir -- -f 这样-f就不会被作为选项。
temp=`getopt -o ab:c:: --long a-long,b-long:,c-long::
     -n 'example.bash' -- "$@"`
if [ $? != 0 ] ; then echo "terminating..." >&2 ; exit 1 ; fi
# note the quotes around `$temp': they are essential!
#set 会重新排列参数的顺序,也就是改变$1,$2...$n的值,这些值在getopt中重新排列过了
eval set -- "$temp"
#经过getopt的处理,下面处理具体选项。
while true ; do
        case "$1" in
                -a|--a-long) echo "option a" ; shift ;;
                -b|--b-long) echo "option b, argument `$2'" ; shift 2 ;;
                -c|--c-long)
                        # c has an optional argument. as we are in quoted mode,
                        # an empty parameter will be generated if its optional
                        # argument is not found.
                        case "$2" in
                                "") echo "option c, no argument"; shift 2 ;;
                                *)  echo "option c, argument `$2'" ; shift 2 ;;
                        esac ;;
                --) shift ; break ;;
                *) echo "internal error!" ; exit 1 ;;
        esac
done
echo "remaining arguments:"
for arg do
   echo '--> '"`$arg'" ;
done

比如使用
./test -a  -b arg arg1 -c
你可以看到,命令行中多了个arg1参数,在经过getopt和set之后,命令行会变为:
-a -b arg -c -- arg1
$1指向-a,$2指向-b,$3指向arg,$4指向-c,$5指向--,而多出的arg1则被放到了最后。