Shell实现多级菜单系统安装维护脚本实例分享

2019-09-23 09:33:04王旭

(3) ReStart $SERVER1 Service
(0) Back
EOF
 read -p "Please enter your choice[0-3]: " input1
 case $input1 in
 1)
  echo -e "n>>>>>>>>>>>$DATE Start $SERVER1">>/log.txt
  $SERVER1_START 2>>/log.txt
  if [ $? == 0 ];then
   echo "Start $SERVER1......................................................[OK]"
  else
   echo "Start $SERVER1......................................................[FAILED]"
  fi
  sleep 5
  clear
  ;;
 2) 
  echo -e "n>>>>>>>>>>>$DATE Stop $SERVER1">>/log.txt
  $SERVER1_STOP 2>>/log.txt
  if [ $? == 0 ];then
   echo "Stop $SERVER1.......................................................[OK]"
  else
   echo "Stop $SERVER1.......................................................[FAILED]"
  fi
  sleep 5
  clear
  ;;
 3)
  echo -e "n>>>>>>>>>>>$DATE ReStart $SERVER1">>/log.txt
  /usr/local/tdoa/php/sbin/php-fpm restart 2>>/log.txt
  $SERVER1_RESTART 2>>/log.txt
  if [ $? == 0 ];then
   echo "Restart $SERVER1....................................................[OK]"
  else
   echo "Restart $SERVER1....................................................[FAILED]"
  fi
  sleep 5
  clear
  ;;
 0)
 clear
 break
 ;;
 *) echo "----------------------------------"
    echo "|          Warning!!!            |"
    echo "|   Please Enter Right Choice!   |"
    echo "----------------------------------"
 for i in `seq -w 10 -1 1`
   do
     echo -ne "bb$i";
     sleep 1;
   done
 clear
 ;;
 esac
 done
;;
#mysql service
2)
clear
while [ "$flag" -eq 0 ]
do
cat << EOF
----------------------------------------
|****Please Enter Your Choice:[0-3]****|
----------------------------------------
(1) Start $SERVER2 Service
(2) Stop $SERVER2 Service
(3) ReStart $SERVER2 Service
(0) Back
EOF
 read -p "Please enter your Choice[0-3]: " input2
 case $input2 in
 1)
  echo -e "n>>>>>>>>>>>$DATE Start $SERVER2">>/log.txt
  $SERVER2_START 2>>/log.txt
  if [ $? == 0 ];then