windows下直接点击startup.bat启动tomcat服务示例代码

2019-09-19 06:46:32丽君


rem Note that NT requires a window name argument when using start.

rem Also note the quoting as JAVA_HOME may contain spaces.

set _RUNJAVA="%JRE_HOME%binjava"

set _RUNJAVAW="%JRE_HOME%binjavaw"

set _RUNJDB="%JAVA_HOME%binjdb"

set _RUNJAVAC="%JAVA_HOME%binjavac"

goto end

:exit

exit /b 1

:end

3、重启tomcat,敲入http://localhost:8080验证,问题解决。

tomcat5需要jdk1.6做支撑,jdk1.5不能够。
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