xajax的FORM例子

2019-09-14 07:28:33于海丽

                        xajax.$('submitButton').value="please wait...";
                        xajax_processForm(xajax.getFormValues("signupForm"));
                        return false;
                }
                </script>
        </head>
        <body>
                <div id="formWrapper">
                        <div id="title">Create a New Account</div>
                        <div id="formDiv">
                                <form id="signupForm" action="javascript:void(null);" onsubmit="submitSignup();">
                                        <div>Username:</div><div><input type="text" name="username" /></div>
                                        <div>Password:</div><div><input type="password" name="newPass1" /></div>
                                        <div>Confirm Password:</div><div><input type="password" name="newPass2" /></div>
                                        <div class="submitDiv"><input id="submitButton" type="submit" value="continue ->"/></div>
                                </form>