Ajax异步传输与PHP实现交互示例

}else{
document.getElementById("majorinfo").style.display="none";//隐藏专业信息的div
}
}
function ajaxok2()
{
if(xmlHttp.readyState == 4 && xmlHttp.status==200)
{
document.getElementById("majorinfo").innerHTML = xmlHttp.responseText;
}
}

</script>