浅析Asp.net MVC 中Ajax的使用

2019-09-14 07:05:24王振洲

一、使用System.Web.Mvc.Ajax

  1.1 System.Web.Mvc.Ajax.BeginForm

  1.2 System.Web.Mvc.Ajax.ActionLink

二、手工打造自己的“非介入式”Javascript”

一、使用System.Web.Mvc.Ajax

 

1.1 System.Web.Mvc.Ajax.BeginForm

     第一步:用Ajax.BeginForm创建Form

  @using (Ajax.BeginForm(
    new AjaxOptions()
    {
      HttpMethod = "post",
      Url = @Url.Action("Index","Reviews"),
      InsertionMode = InsertionMode.Replace,
      UpdateTargetId = "restaurantList",
      LoadingElementId = "loding",
      LoadingElementDuration = 2000
    }))
  {
     <input type="search" name="searchItem"/>
     <input type="submit" value="按名称搜索"/>
  }

       最终生成的form如下:

 <form id="form0" method="post" 
    data-ajax-url="/Reviews"
    data-ajax-update="#restaurantList"
    data-ajax-mode="replace"
    data-ajax-method="post"
    data-ajax-loading-duration="2000"
    data-ajax-loading="#loding"
    data-ajax="true"
    action="/Reviews" novalidate="novalidate">

第二步:创建Ajax.BeginForm的new AjaxOptions()对象的Url指向的Action

 new AjaxOptions()
    {
       ...
      Url = @Url.Action("Index","Reviews")   
      ...
       }
    public ActionResult Index(string searchKey = null)
    {
      var model = _restaurantReviews.Where(r => searchKey == null || r.Name.ToLower().Contains(searchKey.ToLower().Trim()))
        .OrderByDescending(r => r.Rating)
        .Take(100)
        .Select(r=>new RestaurantReview()
        {
          City = r.City,
          Country = r.Country,
          Id = r.Id,
          Name = r.Name,
          Rating = r.Rating
        }).ToList();
      if (Request.IsAjaxRequest())
      {
        System.Threading.Thread.Sleep(1000 * 3);//模拟处理数据需要的时间
        //return View(model)会返回整个页面,所以返回部分视图。
        return PartialView("_RestaurantPatialView", model);
      }
      return View(model);
    }

 注意:

    关于使用System.Web.Mvc.Ajax的说明:

       Controller的Action方法:

         (1)当显式添加[HttpPost],传给System.Web.Mvc.Ajax的AjaxOptions()的HttpMethod只能为 "post",

         (2)当显式添加[HttpGet],传给System.Web.Mvc.Ajax的AjaxOptions()的HttpMethod只能为 "get",

         (3)当都没有显式添加[HttpPost]和[HttpGet],传给System.Web.Mvc.Ajax的AjaxOptions()的HttpMethod可以为 "get"也可以为"post",

      第三步:添加要承载更新页面的html元素,