比较简单实用的PHP无限分类源码分享(思路不错)

2019-04-08 22:19:36刘景俊

 +---------------------+
 11 rows in set

 mysql> select concat(path,"-",id) from tb_kind;
 +---------------------+
 | concat(path,"-",id) |
 +---------------------+
 | 0-1                 |
 | 0-2                 |
 | 0-3                 |
 | 0-4                 |
 | 0-1-5               |
 | 0-1-6               |
 | 0-1-7               |
 | 0-1-5-8             |
 | 0-1-5-9             |
 | 0-1-5-8-10          |
 | 0-1-5-8-11          |
 +---------------------+
 11 rows in set

 mysql> select concat(path,"-",id) as abs from tb_kind order by abs.path;
 ERROR 1054 : Unknown column 'abs.path' in 'order clause'
 mysql> select concat(path,"-",id) as abs from tb_kind order by abs

 +------------+
 | abs        |
 +------------+
 | 0-1        |
 | 0-1-5      |
 | 0-1-5-8    |
 | 0-1-5-8-10 |
 | 0-1-5-8-11 |
 | 0-1-5-9    |
 | 0-1-6      |
 | 0-1-7      |
 | 0-2        |
 | 0-3        |
 | 0-4        |
 +------------+
 11 rows in set
 mysql> select concat(path,"-",id) as,id,name,path abs from tb_kind order by abs;
 ERROR 1064 : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'id,name,path abs from tb_kind order by abs' at line 1
 mysql> select concat(path,"-",id) as abs,
 id,pname,path abs from tb_kind order by abs;
 +------------+----+----------+---------+
 | abs        | id | pname    | abs     |
 +------------+----+----------+---------+
 | 0-1        |  1 | 新闻     | 0       |
 | 0-1-5      |  5 | 体育新闻 | 0-1     |
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