表的创建
| CREATE TABLE `lee` ( `id` int(10) NOT NULL AUTO_INCREMENT, `name` char(20) DEFAULT NULL, `birthday` datetime DEFAULT NULL, PRIMARY KEY (`id`)) ENGINE=InnoDB DEFAULT CHARSET=utf8 |
数据插入：
| insert into lee(name,birthday) values ('sam','1990-01-01'); insert into lee(name,birthday) values ('lee','1980-01-01'); insert into lee(name,birthday) values ('john','1985-01-01'); |
第一种用法:
| SELECT name, CASE WHEN birthday < '1981' THEN 'old' WHEN birthday > '1988' THEN 'yong' ELSE 'ok' END YORN FROM lee |
第二种用法：
| SELECT NAME, CASE name WHEN 'sam' THEN 'yong' WHEN 'lee' THEN 'handsome' ELSE 'good' END as oldname FROM lee |
第三种：当然了，case when 语句还可以复合
| select name, birthday, case when birthday > '1983' then 'yong' when name='lee' then 'handsome' else 'just so so' end from lee; |
在这里用sql语句进行日期比较的话，需要对年加引号，要不然可能结果和预期的结果不同，
当然也可以用year函数来实现
| select name, case when year(birthday) > 1988 then 'yong' when year(birthday) < 1980 then 'old' else 'ok' END from lee; ========================================================== create table penalties ( paymentno INTEGER not NULL, payment_date DATE not null, amount DECIMAL(7,2) not null, primary key(paymentno) ) insert into penalties values(1,'2008-01-01',3.45); insert into penalties values(2,'2009-01-01',50.45); insert into penalties values(3,'2008-07-01',80.45); |
第一题：对罚款登记分为三类，第一类low,包括大于0小于等于40的罚款，第二类moderate大于40到80之间的罚款，第三类high包含所有大于80的罚款
| select payment_date, amount, case when amount >= 0 AND amount < 40 then 'low' when amount >=40 AND amount < 80 then 'moderate' when amount >=80 then 'high' else 'null' END FROM penalties |
第二题:统计出属于low的罚款编号
| select * from ( select paymentno, amount, case when amount >= 0 AND amount < 40 then 'low' when amount >=40 AND amount < 80 then 'moderate' when amount >=80 then 'high' else 'incorrect' end lvl from penalties) as p where p.lvl = 'low' |
PS：Mysql，Case When,Case多个字段
